Question

Multiply : $(\frac{1}{3}{x}^2-\frac{1}{2}x+5)$ by $(\frac{1}{2}{x}^2-\frac{1}{3}x+1)$

Answer: $-\sqrt{6}{x}^4{y}^4+2x^5{y}^4+\sqrt{10}{x}^5{y}^5$

• A. True
• B. False

Answer 1

The correct option is B False

$(\frac{1}{3}{x}^2-\frac{1}{2}x+5)(\frac{1}{2}{x}^2-\frac{1}{3}x+1)$

$=\frac{1}{6}{x}^4-x^3(\frac{1}{9}+\frac{1}{4})+x^2(\frac{1}{3}+\frac{5}{2}+\frac{1}{6})+x(\frac{-1}{2}+\frac{-5}{3})+5$

$=\frac{1}{6}{x}^4-x^3\left(\frac{13}{36}\right)+{3x}^2+x\left(\frac{-13}{6}\right)+5$