Multiply -6 - -2 by -6 - -2

(√(6) + √(2))(√(6) + √(2)) = (√(6) + √(2))^2 It is in the form of (a + b)^2 = (√(6))^2 + 2√(6)×√(2)) + (√(2))^2∵ (a + b)^2 = a^2 + 2ab + b^ ...

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Byju's Answer

Standard VIII

Mathematics

Addition and Subtraction of Algebraic Expression

Multiply √6...

Question

Multiply $(\sqrt{6} + \sqrt{2})$ by $(\sqrt{6} + \sqrt{2})$

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Solution

$(\sqrt{6} + \sqrt{2}) (\sqrt{6} + \sqrt{2})$
$= (\sqrt{6} + \sqrt{2})^{2}$ It is in the form of $(a + b)^{2}$
$= (\sqrt{6})^{2} + 2 \sqrt{6} \times \sqrt{2}) + (\sqrt{2})^{2} ∵ (a + b)^{2} = a^{2} + 2 a b + b^{2}$
$= 6 + 2 \sqrt{12} + 2$
$= 8 + 2 \sqrt{12}$

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Multiply (√6+√2) by (√6+√2)

(√6+√2)(√6+√2)=(√6+√2)2 It is in the form of (a+b)2=(√6)2+2√6×√2)+(√2)2∵(a+b)2=a2+2ab+b2=6+2√12+2=8+2√12

Multiply $(\sqrt{6} + \sqrt{2})$ by $(\sqrt{6} + \sqrt{2})$

$(\sqrt{6} + \sqrt{2}) (\sqrt{6} + \sqrt{2})$
$= (\sqrt{6} + \sqrt{2})^{2}$ It is in the form of $(a + b)^{2}$
$= (\sqrt{6})^{2} + 2 \sqrt{6} \times \sqrt{2}) + (\sqrt{2})^{2} ∵ (a + b)^{2} = a^{2} + 2 a b + b^{2}$
$= 6 + 2 \sqrt{12} + 2$
$= 8 + 2 \sqrt{12}$