Question

Multiply the additive inverse of $\frac{-19}{2}$ with the reciprocal of $38$.

• A. $4$
• B. $\frac{1}{4}$
• C. $\frac{1}{2}$
• D. $\frac{2}{19}$

Answer 1

The correct option is B $\frac{1}{4}$

The additive inverse of $\frac{-19}{2}=\frac{19}{2}$

The reciprocal of $38=\frac{1}{38}$

$⟹\frac{19}{2}\times \frac{1}{38}=\frac{1}{4}$