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Question

Multiply the binomials:
(2pq + 3q2) and (3pq 2q2)

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Solution

(2pq+3q2)(3pq2q2)
= 2pq × (3pq 2q2) + 3q2 × (3pq 2q2)
= 2pq × 3pq 2pq × 2q2 + 3q2 × 3pq 3q2 × 2q2
= 6p2q2 4pq3 + 9pq3 6q4
= 6p2q2 + 5pq3 6q4

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