Question

Multiply the binomials: $\left(y-8\right)$ and $\left(3y-4\right)$

Answer 1

Step 1: Follow the following steps to multiply two binomials.

• Apply distributive law of multiplication.
• Multiply every term of one binomial with every term in the other binomial.
• Look for like terms, if any, and combine them.

Step 2: Multiply $\left(y-8\right)$ and $\left(3y-4\right)$.

$\begin{array}{l}\left(y-8\right)\times \left(3y-4\right)\\ =y\times \left(3y-4\right)-8\left(3y-4\right)\\ =3y^2-4y-24y+32\\ =3y^2-28y+32\end{array}$

Hence the product of $\left(y-8\right)$ and$\left(3y-4\right)$ is $3y^2-28y+32$.