Multiply the binomials:
$(y - 8)$ and $(3 y - 4)$

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Solution

$(y - 8) \times (3 y - 4)$
$= y \times (3 y - 4) - 8 \times (3 y - 4)$
$= y \times 3 y - y \times 4 - 8 \times 3 y - 8 \times (- 4)$
$= 3 y^{2} - 4 y - 24 y + 32$
$= 3 y^{2} - 28 y + 32$

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