Multiply the following binomials by monomials
$3 a b \times (2 a - a b)$

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Solution

Finding the multiplication
Multiplying by the horizontal method
$3 a b \times (2 a - a b) = (3 a b) \times (2 a) - (3 a b) \times (a b) = (3 \times 2) (a b \times a) - (3 \times 1) (a b \times a b) = 6 a^{2} b - 3 a^{2} b^{2}$
Hence, the product of algebraic expression is $6 a^{2} b - 3 a^{2} b^{2}$ .

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