Question

Multiply the following numbers by formula Nikhilam:
(i) $11\times 12$
(ii) $27\times 28$

Answer 1

(i)

$1$. Both numbers have base as $10$

$2$. $11$ is $1$ more than $10$ and $12$ is $2$ more than $10$.

$3$. $\left(1\right)\times \left(2\right)=2$.

$4$. $(11+2)$ or $(12+1)$ = $13$.

$5$. FINAL ANSWER = $132$.

(ii)

$1$. Both numbers have base as $10$

$2$. $27$ is $17$ more than $10$ and $28$ is $18$ more than $10$.

$3$. $\left(17\right)\times \left(18\right)=306$. (since base is $10$ we use $6$ and add $30$ to the following)

$4$. $(27+18)$ or $(28+17)$ = $45$. (Adding $30$ to $45$ we get $75$)

$5$. FINAL ANSWER = $756$.