The correct option is B 5u2v+2uv2
Applying distributive law in multiplication,
uv×(5u+2v)=uv×5u+uv×2v
Applying commutaive law and adding the exponent of repective unknown variables we get,
⇒uv×(5u+2v)=5×u(1+1)×v+2×u×v(1+1)
⇒uv×(5u+2v)=5×u2×v+2×u×v2
⇒uv×(5u+2v)=5u2v+2uv2