Multiply-vi 9-2-2 and 2-3-

Step: Multiplying the given expressions Given, 9𝑥𝑦+2𝑦^2 𝐚𝐧𝐝 &𝐧𝐛𝐬𝐩; 2𝑥−3𝑦 Required product =(9𝑥𝑦+2𝑦^2 )(2𝑥−3𝑦) =9𝑥𝑦(2𝑥−3𝑦)+2𝑦^2 (2𝑥−3𝑦) [Distributive property] ...

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Byju's Answer

Standard IX

Mathematics

Conversion of Numbers Using Logarithms

Multiply:vi 9...

Question

Multiply:
(vi) $9 x y + 2 y^{2} a n d 2 x - 3 y$

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Solution

Step: Multiplying the given expressions
Given, $9 x y + 2 y^{2} a n d 2 x - 3 y$
Required product $= (9 x y + 2 y^{2}) (2 x - 3 y)$ $= 9 x y (2 x - 3 y) + 2 y^{2} (2 x - 3 y)$ [Distributive property] $= 9 x y \times 2 x - 9 x y \times 3 y + 2 y^{2} \times 2 x - 2 y^{2} \times 3 y$ $= 18 x^{2} y - 27 x y^{2} + 4 x y^{2} - 6 y^{3} [a^{m} \times a^{n} = a^{(} m + n)]$ $= 18 x^{2} y - 23 x y^{2} - 6 y^{3}$
Hence, the answer is $18 x^{2} y - 23 x y^{2} - 6 y^{3} .$

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Multiply: (vi) 9xy+2y2 and 2x−3y

Step: Multiplying the given expressions Given, 9xy+2y2 and 2x−3y Required product =(9xy+2y2)(2x−3y) =9xy(2x−3y)+2y2(2x−3y) [Distributive property] =9xy×2x−9xy×3y+2y2×2x−2y2×3y =18x2y−27xy2+4xy2−6y3 [am×an=a(m+n)] =18x2y−23xy2−6y3 Hence, the answer is 18x2y−23xy2−6y3.

Multiply:
(vi) $9 x y + 2 y^{2} a n d 2 x - 3 y$