Multiply $(y - 8)$ and $(3 y - 4)$ .

3 y^{2} - 28 y + 32

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3 y^{2} - 26 y + 32

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3 y^{2} - 20 y + 32

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3 y^{2} + 20 y + 32

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Solution

The correct option is A $3 y^{2} - 28 y + 32$
$(y - 8) \times (3 y - 4)$
$= y (3 y - 4) - 8 (3 y - 4)$
$= 3 y^{2} - 4 y - 24 y + 32$
$= 3 y^{2} - 28 y + 32$

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Multiply (y−8) and (3y−4).

The correct option is A 3y2−28y+32 (y−8)×(3y−4)=y(3y−4)−8(3y−4)=3y2−4y−24y+32=3y2−28y+32

Multiply $(y - 8)$ and $(3 y - 4)$ .

The correct option is A $3 y^{2} - 28 y + 32$
$(y - 8) \times (3 y - 4)$
$= y (3 y - 4) - 8 (3 y - 4)$
$= 3 y^{2} - 4 y - 24 y + 32$
$= 3 y^{2} - 28 y + 32$