Question

$MX$(solid)+$E_1$ $\to$ $M^{+}+X^{-}$; $M^{+}+n{H}_{2}O$ $\to$ $\left[M\right(H_{2}O{)}_n{]}^{+}$+$E_2$; $X^{-}+m{H}_{2}O$ $\to$ $\left[X\right(H_{2}O{)}_m{]}^{-}$+$E_3$

$E_1$, $E_2$ and $E_3$ are energies, then correct statement is :

• A. Compound $\left(MX\right)$ soluble in water if $E_3$-$E_2$>$E_1$
• B. Compound soluble in water $E_3$+$E_2$<$E_1$
• C. Compound soluble in water if $E_1$+$E_2$ >$E_3$
• D. Compound soluble in water if $E_2$+$E_3$>$E_1$

Answer 1

Answer: (D)

Compound soluble in water if $E_2$+$E_3$>$E_1$

Compound will be soluble in water if hydration energy is higher than enthalpy of compound so compound will be soluble in water if $E_2$+$E_3$>$E_1$