My age is 3 years less than twice the age of my brother. Assume that my brother’s age is x and my age is y. then the equation is
A
2x + y = 3
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B
2x - y = 3
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C
3x - 2y = 0
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D
x - 2y = 3
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Solution
The correct option is B 2x - y = 3 Let my brother’s age be x and my age be y. Then, twice the age of my brother is 2x.
My age is equal to 3 less than twice my brother's age.
So, this can be represented as y=2x−3. ∴2x−y=3 is the required equation.