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Standard VII

Mathematics

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My younger si...

Question

Question 79

My younger sister's age today is 3 times what it will be 3 years from now minus 3 times what her age was 3 years ago. Find her present age.

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Solution

Let the present age of my younger sister be x years.
Then, her age after 3 years = (x + 3) years
Also, her age 3 years ago = (x - 3) years
It is given that her present age is 3 times her age after 3 years minus 3 times her age 3 years ago.
Therefore, we obtain the following equation
x = 3(x + 3) - 3(x - 3)
$\Rightarrow x = 3 x + 9 - 3 x + 9 [u s i n g t h e d i s t r i b u t i v e p r o p e r t y] \Rightarrow x = 18 y e a r s$
Hence, her present age is 18 years.

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My sister's age today is 3 times, what it will be 3 years from now - 3 times what her age was 3 years ago. Find the present age

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Applications (Word Problem)

Standard VII Mathematics

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Question 79 My younger sister's age today is 3 times what it will be 3 years from now minus 3 times what her age was 3 years ago. Find her present age.

Question 79

My younger sister's age today is 3 times what it will be 3 years from now minus 3 times what her age was 3 years ago. Find her present age.