n1 and n2 moles of two ideal gases of thermodynamics constant γ1 and γ2 respectively are mixed, for the mixture is –
A
γ1+γ22
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B
n1γ1+n2γ2n1+n2
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C
n1γ2+n2γ1n1+n2
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D
=n1γ1(γ2−1)+n2γ2(γ1−1)n1(γ2−1)+n2(γ1−1)
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Solution
The correct option is D=n1γ1(γ2−1)+n2γ2(γ1−1)n1(γ2−1)+n2(γ1−1) n=n1+n2W=U1+U2nCV=n1CV1+n2CV2=n1Rγ1−1+n2Rγ2−1CP=nCVnCP=n1γ1Rγ1−1+n2γ2Rγ2−1γ=nCPnCV=CPCV n1γ1Rγ1−1+n2γ2Rγ2−1Rn1(γ2−1)+n2R(γ1−1) =n1γ1(γ2−1)+n2γ2(γ1−1)n1(γ2−1)+n2(γ1−1)