N1 molecules of a gas at temperature T1 are mixed with N2 molecules at temperature T2. The resulting temperature of the mixture gas is
A
(T1−T2)2
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B
(N1T1−N2T2)(N1+N2)
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C
(N1T1+N2T2)(N1+N2)
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D
{(N1+N2)2}{T1+T22}
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Solution
The correct option is D(N1T1+N2T2)(N1+N2) (32kT1)×N1+(32kT2)×N2 (by conservation of energy i.e.,energy will remain constant) =(N1+N2)×32kT T1N1+T2N2=(N1+N2)T ∴T=N1T1+N2T2N1+N2