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Question

N1 molecules of a gas at temperature T1 are mixed with N2 molecules at temperature T2. The resulting temperature of the mixture gas is

A
(T1T2)2
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B
(N1T1N2T2)(N1+N2)
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C
(N1T1+N2T2)(N1+N2)
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D
{(N1+N2)2}{T1+T22}
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Solution

The correct option is D (N1T1+N2T2)(N1+N2)
(32kT1)×N1+(32kT2)×N2 (by conservation of energy i.e.,energy will remain constant)
=(N1+N2)×32kT
T1N1+T2N2=(N1+N2)T
T=N1T1+N2T2N1+N2

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