$(n - 10)^{2} + (10 - n)$

Open in App

Solution

The given expression $(n - 10)^{2} + (10 - n)$ can be solved as follows:

$(n - 10)^{2} + (10 - n) = n^{2} + (10)^{2} - (2 \times n \times 10) + (10 - n) (∵ (a - b)^{2} = a^{2} + b^{2} - 2 a b) = n^{2} + 100 - 20 n + 10 - n = n^{2} + (- 20 n - n) + (10 + 100) (C o m b i n i n g l i k e t e r m s) = n^{2} - 21 n + 110$

Hence, $(n - 10)^{2} + (10 - n) = n^{2} - 21 n + 110$ .

Suggest Corrections

Similar questions

Factorise it:-

(n - 10)² + (10 - n)

\frac{1}{10} + \frac{2}{10^{2}} + \frac{3}{10^{3}} + . . . . . . . . . + \frac{n}{10^{n}} + . . . . .

\frac{1}{10} + \frac{2}{10^{2}} + \frac{3}{10^{3}} + . . . . . .

n^{t h}

\frac{n}{10^{n}}

(x + a)^{102} + (x - a)^{102}

(x + b)^{n}

n + 1

Join BYJU'S Learning Program