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Question

If A=067608780,B=011102120,C=223, Calculate AC,BC and (A+B)C. Also, verify that (A+B)C=AC+BC.

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Solution

Gven: A=067608780,B=011102120,C=223
Calculating AC
AC=0676087803×3 2233×1
AC=0(2)+6(2)+7(3)6(2)+0(2)+8(3)7(2)8(2)+0(3)
AC=012+2112+0+2414+16+0=91230
Calculating BC
BC=0111021203×32233×1
BC=0(2)+1(2)+1(3)1(2)+0(2)+2(3)1(2)+2(2)+0(3)3×1
BC=02+32+0+624+0
BC=182
Calculating (A+B)C
(A+B)C=0+06+17+16+10+08+27+18+20+0C
(A+B)C=07850108603×32233×1
(A+B)C=0(2)+7(2)+8(3)5(2)+0(2)+10(3)8(2)+(6)(2)+0(3)3×1
(A+B)C=014+2410+0+3016+12+0
(A+B)C=102028
Solve for proving (A+B)C=AC+BC
Calculating AC+BC
AC+BC=91230+182=9+112+8302=102028
So, (A+B)C=AC+BC
L.H.S.=R.H.S.
Hence proved.

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