Question

Solve the following equation by transposing the terms and check your result:
$3y+4=5y-4$

Answer 1

The given equation is
$3y+4=5y-4$.

Transposing $5y$ from RHS to LHS and transposing $4$ from LHS to RHS, we have
$\Rightarrow 3y-5y=-4-4$
$\Rightarrow -2y=-8$

Divide both the sides by $-2$, we get
y= -8/-2 = 4

So, the value of $y$ is $4$.

Now, let's check for value of $y$ in the eqaution.
$3y+4=5y-4$
$\Rightarrow 3\left(4\right)+4=5\left(4\right)-4$
$\Rightarrow 12+4=20-4$
$\Rightarrow 16=16$
LHS = RHS. So, the value of $y$ is correct.