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Standard XII

Physics

Power Delivered and Heat Dissipated in a Circuit

Two capacitor...

Question

Two capacitors with capacitances $30 μ F and 60 μ F$ are charged to potentials 20 V and 10 V respectively. Then they are disconnected from their respective batteries and connected to each other so that plates with same polarities connected together. The heat produced after the capacitors are connected as described is

0.2 mJ

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1.0 mJ

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5 mJ

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0.5 mJ

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Solution

The correct option is B 1.0 mJ
H = Loss of energy $= \frac{1}{2} (\frac{C_{1} C_{2}}{C_{1} + C_{2}}) (V_{1} - V_{2})^{2}$

$= \frac{1}{2} [20] \times 10^{- 6} \times 100 = 10^{- 3} J$

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The correct option is B 1.0 mJH = Loss of energy =12(C1C2C1+C2)(V1−V2)2 =12[20]×10−6×100=10−3 J

The correct option is B 1.0 mJ
H = Loss of energy $= \frac{1}{2} (\frac{C_{1} C_{2}}{C_{1} + C_{2}}) (V_{1} - V_{2})^{2}$

$= \frac{1}{2} [20] \times 10^{- 6} \times 100 = 10^{- 3} J$