if $l_{1}$ and $l_{2}$ are the lengths of air column for the first and second resonance when a tuning fork of frequency $n_{0}$ is in resonacne with a resonance tube. Then, the speed of sound in air is equal to

\frac{n_{0}}{2} (4 l_{2} - l_{1})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 n_{0} (4 l_{2} - l_{1})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

n_{0} (4 l_{2} - l_{1})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 n_{0} (4 l_{2} - l_{1})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 n_{0} (4 l_{2} - l_{1})$
$\frac{λ}{4} = l_{1} + θ$
$\frac{2 λ}{4} = l_{2} + e \Rightarrow \frac{λ}{2} = (λ_{2} - λ_{1})$

Suggest Corrections

Similar questions

Q. If

l_{1}

and

l_{2}

are the lengths of air column for the first and second resonance when a tuning fork of frequency n is sounded on a resonance tube, then the distance of the displacement antinode from the top end of the resonance tube is :

Q. A tuning fork of frequency

480 H z

is used in an experiment for measuring speed of sound

(v)

in air by resonance tube method. resonance is observed to occur at two successive lengths of the air column,

l_{1} = 30 c m

and

l_{2} = 70 c m

. Then

v

is equal to:

Q. In a resonance tube experiment, tuning fork A is in resonance with air column of length

40 cm

and tuning fork B is in resonance with air column of length

41 cm

.
Two tuning forks A and B sounded together produce

10

beats per second. Calculate the frequencies of forks.
(Assume fundamental mode for air column)

Q. In a closed tube when air column is 20 cm it is in resonance with tuning fork A. When the length is increased by 2 cm then the air column is in resonance with tuning fork B. When A and B are sounded together they produce 8 beats per second. The frequencies of the tuning forks A and B are (in Hz) :

In a resonance - column experiment to measure the velocity of sound, the first resonance is obtained at a length $l_{1}$ and the second resonance at a length $l_{2}$ . Which of the following is (are) correct?

Join BYJU'S Learning Program

if l1 and l2 are the lengths of air column for the first and second resonance when a tuning fork of frequency n0 is in resonacne with a resonance tube. Then, the speed of sound in air is equal to

The correct option is B 2n0(4l2−l1)λ4=l1+θ 2λ4=l2+e⇒λ2=(λ2−λ1)

if $l_{1}$ and $l_{2}$ are the lengths of air column for the first and second resonance when a tuning fork of frequency $n_{0}$ is in resonacne with a resonance tube. Then, the speed of sound in air is equal to

The correct option is B $2 n_{0} (4 l_{2} - l_{1})$
$\frac{λ}{4} = l_{1} + θ$
$\frac{2 λ}{4} = l_{2} + e \Rightarrow \frac{λ}{2} = (λ_{2} - λ_{1})$