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Byju's Answer

Standard IX

Physics

Speed of Sound vs Speed of Light

if l1 and l2 ...

Question

if $l_{1}$ and $l_{2}$ are the lengths of air column for the first and second resonance when a tuning fork of frequency $n_{0}$ is in resonacne with a resonance tube. Then, the speed of sound in air is equal to

\frac{n_{0}}{2} (4 l_{2} - l_{1})

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2 n_{0} (4 l_{2} - l_{1})

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n_{0} (4 l_{2} - l_{1})

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4 n_{0} (4 l_{2} - l_{1})

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Solution

The correct option is B $2 n_{0} (4 l_{2} - l_{1})$
$\frac{λ}{4} = l_{1} + θ$
$\frac{2 λ}{4} = l_{2} + e \Rightarrow \frac{λ}{2} = (λ_{2} - λ_{1})$

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if l1 and l2 are the lengths of air column for the first and second resonance when a tuning fork of frequency n0 is in resonacne with a resonance tube. Then, the speed of sound in air is equal to

The correct option is B 2n0(4l2−l1)λ4=l1+θ 2λ4=l2+e⇒λ2=(λ2−λ1)

if $l_{1}$ and $l_{2}$ are the lengths of air column for the first and second resonance when a tuning fork of frequency $n_{0}$ is in resonacne with a resonance tube. Then, the speed of sound in air is equal to

The correct option is B $2 n_{0} (4 l_{2} - l_{1})$
$\frac{λ}{4} = l_{1} + θ$
$\frac{2 λ}{4} = l_{2} + e \Rightarrow \frac{λ}{2} = (λ_{2} - λ_{1})$