Question

Third overtone of a closed organ pipe is equal to the second harmonic of an open organ pipe. Then the ratio of their length is equal

• A. $\left(\frac{12}{11}\right)$
• B. $\left(\frac{4}{7}\right)$
• C. $\left(\frac{7}{4}\right)$
• D. $\left(\frac{11}{12}\right)$

Answer 1

The correct option is C $\left(\frac{7}{4}\right)$

$\frac{7v}{4l_1}=\frac{2v}{2l_2}$
$\therefore \frac{l_1}{l_2}=\frac{7}{4}$