The locus of orthocentre of the triangle formed by three tangents to the parabola $4 x^{2} - 8 x - 3 y + 10 = 0$ is

16 y = 29

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16 x = 19

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16 x = 13

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16 y = 35

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Solution

The correct option is A $16 y = 29$
The orthocentre of triangle lie on the directrix
$4 (x - 1) 2 = 3 (y - 2)$
Equation of directrix $= y - 2 = - \frac{3}{16}$
$\Rightarrow 16 y = 29$

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Similar questions

The orthocentre of any triangle formed by three tangents of parabola lies on the __ of the parabola.

t_{1}, t_{2}, t_{3}

y^{2} = 4 a x

(- a, a (t_{1} + t_{2} + t_{3} + t_{1} t_{2} t_{3}))

A (1, 2), B (4, - 4)

^{'} C^{'}

y^{2} = 4 x

x + 3 y - 10 = 0

6 x^{2} + x y - y^{2} = 0

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