A uniform chain of length $3 m$ and mass $3 kg$ overhangs a smooth table with $2 m$ laying on the table. If $k$ is the kinetic energy of the chain in joule as it completely slips off the table, then the value of $k$ is ______.

Take $g = 10 {m/s}^{2}$

40.0

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40.00

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Solution

From law of conservation of mechanical energy,

$K E_{i} + P E_{i} = K E_{f} + P E_{f}$

$\Rightarrow 0 + (1 \times 10 \times - 0.5) = k + (3 \times 10 \times - 1.5)$

$\Rightarrow k = 40 J$

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A uniform chain of length 3 m and mass 3 kg overhangs a smooth table with 2 m laying on the table. If k is the kinetic energy of the chain in joule as it completely slips off the table, then the value of k is ______. Take g=10 m/s2

From law of conservation of mechanical energy, KEi+PEi=KEf+PEf ⇒0+(1×10×−0.5)=k+(3×10×−1.5) ⇒k=40 J

A uniform chain of length $3 m$ and mass $3 kg$ overhangs a smooth table with $2 m$ laying on the table. If $k$ is the kinetic energy of the chain in joule as it completely slips off the table, then the value of $k$ is ______.

Take $g = 10 {m/s}^{2}$

From law of conservation of mechanical energy,

$K E_{i} + P E_{i} = K E_{f} + P E_{f}$

$\Rightarrow 0 + (1 \times 10 \times - 0.5) = k + (3 \times 10 \times - 1.5)$

$\Rightarrow k = 40 J$