wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The difference in the oxidation numbers of the two types of sulphur atoms in Na2S4O6 is

Open in App
Solution

Structure of S4O26 is


Difference in oxidation state is +5-0 = +5.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Calculating Oxidation Number
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon