The circle passing through the point (–1,0) and touching the y−axis at (0,2) also passes through the point
A
Option a missing
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B
(−4,0)
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C
Option b missing
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D
Option c missing
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Solution
The correct option is B(−4,0)
The equation of the circle directing y−axis at (0,2) can be put in the form (x–h)2+(y–2)2=h2
which will pass through (–1,0) if (–1–h)2+4=h2 ⇒h=−52
Thus the equation of the circle is (x+52)2+(y−2)2=(52)2
which passes through (−4,0)