Which one of the following is correct order of the size of iodine species?

I > I^{-} > I^{+}

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I^{+} > I^{-} > I

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I > I^{+} > I^{-}

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I^{-} > I > I^{+}

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Solution

The correct option is D $I^{-} > I > I^{+}$
Positive ion is always smaller and negative ion is always larger than the parent atom. So, the correct order of the size of iodine species will be $I^{-} > I > I^{+}$

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