CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Gibbs Free Energy & Spontaneity

Find the magn...

Question

Find the magnitude of enthalpy of formation of $H C l$ (in $k j m o l^{- 1}$ ) if the bond dissociation enthalpy of $H_{2}$ , $C l_{2}$ and $H C l$ are 434, 242 and 431 kj $m o l^{- 1}$ respectively.

A

105

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

39

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

93

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

99

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $93$
$H_{2} + C l_{2} \to 2 H C l$

$Δ H = 434 + 242 - 2 (431) = - 186$

$∴ Δ H_{f} = \frac{Δ H}{2} = - 93$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Bond dissociation enthalpy of

H_{2}, C l_{2}

H C l

are 434, 242 and 431 kJ

m o l^{- 1}

Enthalpy of formation of

H C l

Q. Bond dissociation enthalpy of

H_{2}, C l_{2}

H C l

434, 242

431 {kJ mol}^{- 1}

respectively.
Enthalpy of formation of

H C l

{kJ mol}^{- 1}

X

, then value of

X

Q. The bond dissociation energy of gaseous

H_{2}

C l_{2}

H C l

104

58

103

m o l^{- 1}

respectively. The enthalpy formation for

H C l

Q. The bond enthalpies of

H - H, C l - C l

H - C l

435, 243

431

m o l^{- 1}

, respectively. The enthalpy of formation of

H C l (g)

Q. Bond dissociation enthalpies of

H_{2_{(} g)}

N_{2_{(} g)}

K J

m o l^{- 1}

K J

m o l^{- 1}

, respectively and enthalpy of formation of

N H_{3_{(} g)}

- 46 K J

m o l^{- 1}

What is the enthalpy of atomization of

N H_{3_{(} g)}

and the average bond enthalpy of

N - H

bond respectively (in

K J

m o l^{- 1}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Gibbs Free Energy

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Gibbs Free Energy & Spontaneity

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon