Question

If fore bearing of a line $\text{N}{30}^o\text{E}$, the back bearing of the line is :

• A. $\text{S}{30}^o\text{W}$
• B. $\text{N}{30}^o\text{E}$
• C. $\text{S}{30}^o\text{E}$
• D. $\text{N}{30}^o\text{W}$

Answer 1

The correct option is A $\text{S}{30}^o\text{W}$

(c)
If the fore bearing of a line is given as the quadrantal bearing,

Back bearing = Numerically equal to fore bearing.

Just change N for S, and vice versa and E for W, and vice versa.

Fore bearing of a line $\text{= N}{30}^o\text{E}$

From above explanation,

Back bearing of a line $\text{= S}{30}^o\text{W}$