Question

$N_2+3H_2\to 2{NH}_3$
If $15L$ hydrogen is available for the reaction above, what volume of ${NH}_3$ will be formed?
Assume an excess of nitrogen for this reaction and STP conditions.

• A. $22.5L$
• B. $15L$
• C. $30L$
• D. $10L$

Answer 1

The correct option is D $10L$

$1mole$ of Nitrogen requires $3moles$ of Hydrogen, i.e. $1L$ of Nitrogen require $3L$ of Hydrogen.

$1L$ of Nitrogen $\to$ $3L$ Hydrogen

$\left(x\right)$ $\to$ $15L$ Hydrogen

$x=\frac{15}{3}=15Litres$ Nitrogen.

$1L$ Nitrogen produces $2L$ Ammonia, so $5L$ Nitrogen produces $10L$ Ammonia.