Question

$N_2+3H_2\rightleftharpoons 2N{H}_3$
Which is correct statement if $N_2$ is added at equilibrium condition?

• A. The equilibrium will shift to forward direction because according to IInd law of thermodynamics, the entropy must increases in the direction of spontaneous reaction
• B. The condition for equilibrium is $G\left(N_2\right)+3G\left(H_2\right)=2G\left(N{H}_3\right)$ where, G is Gibbs free energy per mole fo the gaseous species measured at that partial pressure. The condition of equilibrium is unaffected by the use of catalyst, which increases the rate of both the forward and backward reactions to the same extent
• C. The catalyst will increase the rate fo forward reaction by $\alpha$ and that of backward reaction by $\beta$
• D. Catalyst will not alter the rate fo either fo the reaction

Answer 1

The correct option is B The condition for equilibrium is $G\left(N_2\right)+3G\left(H_2\right)=2G\left(N{H}_3\right)$ where, G is Gibbs free energy per mole fo the gaseous species measured at that partial pressure. The condition of equilibrium is unaffected by the use of catalyst, which increases the rate of both the forward and backward reactions to the same extent

At equilibrium $△$ G = 0
G(reactants) = G(products)
$G\left(N_2\right)+3G\left(H_2\right)=2G\left(N{H}_3\right)$