Question

$N_2$ and $O_2$ are converted into monoanions $N_2^{-}$ and $O_2^{-}$ respectively, which of the following statements is wrong?

• A. In $O_2^{-}$ , bond length increases
• B. $N_2^{-}$ becomes diamagnetic
• C. In $N_2^{-}$, the $N-N$ bond weakens
• D. In $O_2^{-}$ , the $O-O$ bond order decreases

Answer 1

The correct option is A In $O_2^{-}$ , bond length increases

Bond order $\alpha \frac{1}{Bondlength}=\frac{Numberofbondinge-Numberofantibondinge}{2}$

For $N_2$

Bind order $=\frac{10-4}{}$

$=\frac{6}{2}$

$=3$

For $N_2^{-}$

Bond order $=\frac{10-5}{2}$

$=\frac{5}{2}$

$=2.5$

In case of $N_2^{-}$ one $e^{-}$ present in antibonding orbital. So it is paramagnetic.

For $O_2$

Bod order $=\frac{10-6}{2}$

$=\frac{4}{2}$

$=2$

Bond order $=\frac{10-7}{2}$

$=\frac{3}{2}$

$=1.5$

$SO$ in $O_2^{-}$ Bond length increases.