$N_{2} (g) + O_{2} (g) ⇌ 2 N O (g) Δ H = Q c a l s$ , where Q is positive.
In the above reaction which is the essential condition for the higher production of $N O$ ?

High temperature

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

High pressure

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Low temperature

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Low pressure

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A High temperature
$N_{2} (g) + O_{2} (g) ⇌ 2 N O (g) - Q c a l s$
The above reaction is endothermic so for higher production of $N O$ , the temperature should be high and as the no. of moles on both sides of equilibrium are equal so pressure would not be having any impact on equilibrium.

Suggest Corrections

Similar questions

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g) Δ H = Q c a l s

N O

$N_2 ~+ ~O_2 ~\rightleftharpoons~ 2NO ~+~ (-Q cals)$

In the above reaction which is the essential condition for the higher production of $N O$

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g) Δ H = - Q C a l

S O_{3}

N_{2} - O_{2} ⇌ 2 N O - Q c a l s

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g), Δ H = + Q c a l

S O_{3}

Join BYJU'S Learning Program