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Question

N2O4 is 20% dissociated at 27oC and 760 torr. The density of the equilibrium mixture is:

A
3.1 g/L
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B
6.2 g/L
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C
12.4 g/L
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D
18.6 g/L
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Solution

The correct option is B 3.1 g/L
Density, d=(P.Mav)RT

N2O4 is 20% dissociated

N2O4x(x-0.2x)2NO20(0.4x)
Moles of mixture at eqm. =0.4x+0.8x
Mav=0.4x×MNO2+0.8x×MN2O4(0.4+0.8)x=0.4x×46+0.8x×921.2x=76.66g/mole
760 torr=1 atm,T=300K,R=0.082 atm.L/mol/K
d=(1×76.66)0.082×300=3.1 g/L

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