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Byju's Answer
Standard XII
Chemistry
Rate of Reaction
N2O5 decompos...
Question
N
2
O
5
decomposes according to equation :
2
N
2
O
5
→
4
N
O
2
+
O
2
What does
d
[
O
2
]
d
t
denote?
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Solution
2
N
2
O
5
→
4
N
O
2
+
O
2
d
(
O
2
)
d
t
represents the change in concentration of
O
2
with respect to time
Therefore,
d
(
O
2
)
d
t
denotes the rate of formation of
O
2
.
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Similar questions
Q.
N
2
O
5
decomposes according to equation :
2
N
2
O
5
→
4
N
O
2
+
O
2
What does
−
d
[
N
2
O
5
]
d
t
denote?
Q.
N
2
O
5
decomposes according to equation :
2
N
2
O
5
→
4
N
O
2
+
O
2
What is the unit of rate of this reaction?
Q.
2
N
2
O
5
→
4
N
O
2
+
O
2
If
−
d
[
N
2
O
5
]
d
t
=
k
1
[
N
2
O
5
]
d
[
N
O
2
]
d
t
=
k
2
[
N
2
O
5
]
d
[
O
2
]
d
t
=
k
3
[
N
2
O
5
]
What is the relation between
k
1
,
k
2
a
n
d
k
3
?
Q.
Dinitrogen pentaoxide decomposes as
2
N
2
O
5
→
4
N
O
2
+
O
2
.
the rate can be given in three ways
−
d
[
N
2
O
5
]
d
t
=
k
1
[
N
2
O
5
]
,
d
[
N
O
2
]
d
t
=
k
2
[
N
2
O
5
]
,
d
[
O
2
]
d
t
=
k
3
[
N
2
O
5
]
The relation between the rate constants
k
1
,
k
2
a
n
d
k
3
is:
Q.
For the reaction
2
N
2
O
5
→
4
N
O
2
+
O
2
, if
−
d
[
N
2
O
5
]
d
t
=
k
1
[
N
2
O
5
]
,
d
[
N
O
2
]
d
t
=
k
2
[
N
2
O
5
]
,
d
[
O
2
]
d
t
=
k
3
[
N
2
O
5
]
.
What is the relation between
k
1
,
k
2
and
k
3
?
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