N -2 - 4 - 6 - 8 - 10 - 100- How many zeroes are there at the end of N -A- 24B- 13C- 15D- 12

The correct option is D 12N = 2 × 4 × 6 × 8 × 10 ×……× 100 =2^50× (1 × 2 × 3 × 4 ×……× 50) =2^50× 50! So, highest power of 5 = Number of zeros = 10 + 2 = 12 ...

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Quantitative Aptitude

Number of Zeroes in a Number

N =2 × 4 × 6 ...

Question

$N = 2 \times 4 \times 6 \times 8 \times 10 \times \dots \dots \times 100$ . How many zeroes are there at the end of N?

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Solution

The correct option is C 12
$N = 2 \times 4 \times 6 \times 8 \times 10 \times \dots \dots \times 100$
$= 2^{50} \times (1 \times 2 \times 3 \times 4 \times \dots \dots \times 50)$
$= 2^{50} \times 50!$
So, highest power of 5 = Number of zeros
= 10 + 2 = 12

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N=2×4×6×8×10×……×100. How many zeroes are there at the end of N?

The correct option is C 12N=2×4×6×8×10×……×100 =250×(1×2×3×4×……×50) =250×50! So, highest power of 5 = Number of zeros = 10 + 2 = 12

$N = 2 \times 4 \times 6 \times 8 \times 10 \times \dots \dots \times 100$ . How many zeroes are there at the end of N?

The correct option is C 12
$N = 2 \times 4 \times 6 \times 8 \times 10 \times \dots \dots \times 100$
$= 2^{50} \times (1 \times 2 \times 3 \times 4 \times \dots \dots \times 50)$
$= 2^{50} \times 50!$
So, highest power of 5 = Number of zeros
= 10 + 2 = 12