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Question

f(x) attains maximum value when x equals

A
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B
2
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1
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Solution

The correct option is A 0
f(x)=3x4+4x312x2+a.
f(x)=12x3+12x224x
=12x(X2+x2)=12x(x+2)(x1)


Clearly f(x) changes its sign from +ve to ve in the neighbourhood of 0, hence f(x) attains maximum value at x=0.
f(x) changes its sign from ve to +ve in the neighbourhood of x=1 & x=2.

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