CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 200 V shunt motor takes 10 A when running on no load. At higher loads the brush drop is 2 V and at light loads it is negligible. The stray load loss at a line current of 100 A is 50% of no load loss. If armature and field resistance is 0.2 Ω and 100 Ω respectively, then the power loss in the motor is ____kW
  1. 5.1

Open in App
Solution

The correct option is A 5.1
No load loss = 200 x 10 = 2000 W

If=200100=2A

Core loss =(200×8)+(82×0.2)

=1587.2W



At load :
Stray load loss = 0.5 x 2000 = 1000 W


PL=(I2aRa+VbrushIa+Pstray)+(Pcore+Pshunt field)

PL=(982×0.2)+(2×98)+1000+1587.2+(200×2)

PL=5.104 kW

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Torque on a Magnetic Dipole
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon