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Question

In a triangle ABC, r1,r2,r3 are the ex-radii of the ex-circles. If a=r1+r2+r3r and b=r1r2r3r3, where r is the inradius then the minimum value of ((amin3)tan2A+(bmin9)cot2A) is

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Solution

In any triangle ABC, 1r=1r1+1r2+1r3

r1+r2+r3331r1+1r2+1r3=3r Using A.M.H.M

r1+r2+r3r9

Minimum of r1+r2+r3r=9

amin=9

Similarly, (r1r2r3)1/331r1+1r2+1r3 Using G.M.H.M

r1r2r3r327 bmin=27

(amin3)tan2A+(bmin9)cot2A=3tan2A+3cot2A

=3(tan2A+cot2A)min=6,

Minimum value of the expression is 6.

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