In any triangle ABC, 1r=1r1+1r2+1r3
r1+r2+r33≥31r1+1r2+1r3=3r Using A.M.≥H.M
r1+r2+r3r≥9
Minimum of r1+r2+r3r=9
amin=9
Similarly, (r1r2r3)1/3≥31r1+1r2+1r3 Using G.M.≥H.M
r1r2r3r3≥27 ⇒bmin=27
(amin3)tan2A+(bmin9)cot2A=3tan2A+3cot2A
=3(tan2A+cot2A)min=6,
⇒ Minimum value of the expression is 6.