Question

The periodic table consists of $18$ groups, An isotope of copper, on bombardment with protons, undergoes a nuclear reaction yielding element $X$ as shown below. To which group, element $X$ belongs in the periodic table ?

${}_{29}^{63}\text{Cu}{+}_1^{1}H\to 6_0^{1}n+\alpha +2_1^{1}H+X$

Answer 1

${}_{29}^{63}Cu{+}_1^{1}H\to 6_0^{1}n+\alpha {(}_2^{4}He)+2_1^{1}H+{(}_{26}^{52}Fe)$

$Fe$ belongs to group $-8$.