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Question

In compound [M(CO)n]z, the correct match for highest ′M−C′ bond length for given M, n and z respectively :

A
M=Mn; n=6; z=+1
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B
M=Cr; n=6; z=0
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C
M=Ti; n=6; z=2
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D
M=V; n=6; z=1
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Solution

The correct option is A M=Mn; n=6; z=+1
In metal carbonyls, the bond order of MC increases and CO decreases.

Metals with high oxidation state shows least back bonding as they have least tendency to donate. And the MC bond order will be lowest. So its bond length will be highest.

metal has highest oxidation state in option d,
M=Mn; n=6; z=+1

Thus, option (d) is correct.

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