In compound [M(CO)n]z, the correct match for highest ′M−C′ bond length for given M, n and z respectively :
A
M=Mn;n=6;z=+1
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B
M=Cr;n=6;z=0
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C
M=Ti;n=6;z=−2
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D
M=V;n=6;z=−1
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Solution
The correct option is AM=Mn;n=6;z=+1 In metal carbonyls, the bond order of M−C increases and C−O decreases.
Metals with high oxidation state shows least back bonding as they have least tendency to donate. And the M−C bond order will be lowest. So its bond length will be highest.
metal has highest oxidation state in option d, M=Mn;n=6;z=+1