A jar contains 24 marbles of which some are green and others are blue. If a marble is drawn randomly from the jar, the probability that it is green is $\frac{2}{3}$ . Find the probability of taking blue marbles from the jar.

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Solution

Given,

Total number of marbles =24

P(green marbles) $= \frac{2}{3}$

We know that,

P(green marbles) + P(blue marbles) =1

Because the sum of probabilities of an event and its complementary event is always 1.

$\Rightarrow$ P(blue marbles) = 1 - P(green marbles) = $1 - \frac{2}{3} = \frac{1}{3}$

Therefore, P(blue marbles) $= \frac{1}{3}$

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A jar contains 24 marbles of which some are green and others are blue. If a marble is drawn randomly from the jar, the probability that it is green is $\frac{2}{3}$ . Find the probability of taking blue marbles from the jar.

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A jar contains 24 marbles of which some are green and others are blue. If a marble is drawn randomly from the jar, the probability that it is green is 23. Find the probability of taking blue marbles from the jar.

Given, Total number of marbles =24 P(green marbles)=23 We know that, P(green marbles) + P(blue marbles) =1 Because the sum of probabilities of an event and its complementary event is always 1. ⇒ P(blue marbles) = 1 - P(green marbles) =1−23=13 Therefore, P(blue marbles) =13

A jar contains 24 marbles of which some are green and others are blue. If a marble is drawn randomly from the jar, the probability that it is green is $\frac{2}{3}$ . Find the probability of taking blue marbles from the jar.