Question

Write first four terms of the AP, when the first term a and common difference d are given as follows:
(i) a= -2, d=0
(ii) a=4, d=-3
(iii) a= -1.25, d= -0.25

Answer 1

(i)

Here, difference between any two consecutive terms which is also called common difference is equal to 0.

First term = a = -2, d=0

Second term = a+d = -2 + 0 = -2

Third term = second term + d = -2 + 0 = -2

Fourth term = third term + d = -2 + 0 = -2

Therefore, first four terms are: -2, -2, -2, -2

(ii)

First term = a = 4, d=-3

Second term = a+ d = 4 -3 = 1

Third term = second term + d = 1-3 = -2

Fourth term = third term + d = -2 -3 = -5

Therefore, first four terms are: 4, 1, -2, -5

(iii)

First term = a =-1.25, d = -0.25

Second term = a+ d = -1.25 - 0.25 = -1.50

Third term = second term + d = -1.50 -0.25 = -1.75

Fourth term = third term + d = -1.75 -0.25 = -2

Therefore, first four terms are: -1.25, -1.50, -1.75,-2