Three aone dimensional mechanical waves in an elastic medium are given as y1- 2A sin - t-kx -y2- 2A sin - -kx- y3- 2A sin - t-kx-4 - For any value of - - the maximum displacement amplitude of the medium particles would be

(y1+y3 )→ Standing waves (y1+y3 )→ Max amplitude will be 4A Now ( y1+y2+y3 )_max= 4A+2A= 6A ...

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Three aone dimensional mechanical waves in an elastic medium are given as $y 1 = 2 A s i n (ω t - k x), y 2 = 2 A s i n (ω - k x + ϕ)$
$y 3 = 2 A s i n (ω t + k x + \frac{π}{4})$ . For any value of $ϕ$ , the maximum displacement amplitude of the medium particles would be

5 A

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3 A

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6 A

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4 A

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Similar questions

y_{1} = 3 A s i n (ω t - k x)

y_{2} = A s i n (ω t - k x + π)

y_{3} = 2 A s i n (ω t + k x)

y_{1} = A sin (ω t - k x)

y_{2} = A sin (ω t - k x + ϕ)

\sqrt{2} A

ϕ

y_{1} = A sin (ω t - k x)

y_{2} = A sin (ω t - k x + ϕ)

\sqrt{2} A

ϕ

y_{1}

sin (ω t - k x)

y_{2} (x, t)

sin (2 ω t - 2 k x)

y_{1} = 2 a s i n (ω t - k x)

y_{2} = 2 a s i n (ω t - k x - θ)

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