wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a zoo, a panda slept 40 hours in 5 days and a tiger slept 42 hours in 6 days. Which animal slept more hours in a day if they sleep equal hours every day?

Open in App
Solution

The panda slept 40 hours in 5 days
=> Number of hours the panda slept in a day = 40 ÷ 5
From the multiplication table of 5, we know that 5 × 8 = 40.
Since division is the reverse of multiplication, 40 ÷ 5 = 8
So the panda slept 8 hours a day.

The tiger slept 42 hours in 6 days.
=> Number of hours the tiger slept in a day = 42 ÷ 6
From the multiplication table of 6, we know that 6 × 7 = 42.
Since division is the reverse of multiplication, 42 ÷ 6 = 7
So the tiger slept 7 hours a day.
Thus, the panda slept more in a day. [8>7]

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of the first n odd natural numbers = n^2
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon