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Representation of Cell

" N2H4 hydra...

Question

" $N_{2} H_{4}$ (hydrazine) reduces iodine to $I^{-}$ and in the process, is oxidised to $N_{2}$ gas."
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Solution

Hydrazine $(N_{2} H_{4})$ reduces iodine to $I^{-}$ and in this process, it itself is oxidised to $N_{2}$ gas.
The reaction is as follows:
$N_{2} H_{4} + 2 I_{2} ⟶ N_{2} + 4 H^{+} + 4 I^{-}$

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