$N_{2} O_{4}$ has a molecular weight 92. Find the total number of electrons in one gram mole of that oxide

4.6N

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46N

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23N

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2.3N

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Solution

The correct option is B
46N

Oxide of nitrogen is $N_{2} O_{4}$

$N o . o f e l e c t r o n s i n o n e m o l e = \frac{W_{t}}{M . W_{t}} \times N \times N o . o f e l e c t r o n s i n o n e m o l e c u l e$

= $1 \times N \times 46 (n o o f e^{-} i n o n e m o l e c u l e o f N_{2} O_{4})$

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