Question

$N_2{O}_4⟶2N{O}_2$
For this reaction relate $\Delta H$ and $\Delta U$.

• A. $\Delta H$ =$\Delta U$
• B. $\Delta H$ > $\Delta U$
• C. $\Delta H$ < $\Delta U$
• D. None of these

Answer 1

The correct option is B $\Delta H$ > $\Delta U$

As we know,
$\Delta H$ =$\Delta U+\Delta n_{g}RT$
here,
$N_2{O}_4⟶2N{O}_2$
$\Delta n_g=+1$
so,
$\Delta H$ > $\Delta U$