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Byju's Answer
Standard IX
Mathematics
Polynomial and Its General Form
n3=3n2+2n=132...
Question
n
3
=
3
n
2
+
2
n
=
1320
. Find the value of n.
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Solution
n
3
=
3
n
2
+
2
n
=
1320
n
(
n
2
−
3
n
+
2
)
n
(
n
−
1
)
(
n
−
2
)
=
1320
(
10
)
(
11
)
(
12
)
=
1320
∴
n
=
12
[
∵
12
×
(
12
−
1
)
×
(
12
−
2
)
12
×
11
×
10
=
1320
]
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Similar questions
Q.
Find the sum of
n
terms of the series whose
n
t
h
term is
n
3
+
3
n
2
+
2
n
+
2
n
2
+
2
n
.
Q.
Find the sum of the series whose nth term is:
(i) 2n
2
− 3n + 5
(ii) 2n
3
+ 3n
2
− 1
(iii) n
3
− 3
n
(iv) n (n + 1) (n + 4)
(v) (2n − 1)
2
Q.
Let
X
=
x
{
x
:
x
=
n
3
+
2
n
+
1
,
n
∈
R
}
and
Y
=
{
x
:
x
=
3
n
2
+
7
,
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∈
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}
then
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∩
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is a subset of
Q.
Match the numbers in column-I with the rules in column- II
No
Column-I
No
Column-II
1
30
a
n
3
+
n
/
2
2
63
b
3
n
2
+
3
3
66
c
n
3
+
4
4
110
d
n
2
−
2
n
5
127
e
n
3
−
3
n
f
2
n
2
−
1
Which rule the number 30 follows?
Q.
The value of
lim
n
→
∞
{
√
n
+
1
+
√
n
+
2
+
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.
.
.
.
+
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n
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}
is
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